Ratio and Proportion- Aptitude Questions and Answers

 If R:S = 0.01:0.11 and S:T = 2.2:1, Find R:S:T? A) 2:2:1 B) 20:22:10 C) 20:2:1 D) 2:22:10 Correct Answer : 2:22:10 Explanation :R:S = 0.01:0.11 = 1:11 S:T = 2.2:1 = 22:10 Therefore for the ratio R:S:T R:S = 1*22:11*22 S:T = 22*11:10*11 R:S:T = 1*22 : 11*22 : 10*11 =1*2:11*2:10*1 =2:22:10 In a school, Under a Saving Scheme, Rekha saves 3/2 times the savings of Bindu, Geeta saves 4 times the savings of Rekha. Find the ratio of the savings of all the three in least terms? A) 12 : 13 : 12 B) 12 : 3 : 12 C) 2 : 3 : 4 D) 2 : 3 : 12 Correct Answer : 2 : 3 : 12 Explanation :As is given R = 1.5B G = 4R = 4*1.5 = 6 So ratio of the savings their saving B : R : G = 1 : 1.5 : 6 = 1 : 3/2 : 6 = 2 : 3 : 12 The ratio of savings of Bindhu to Rekha to Geeta is 2 : 3 : 12 A certain sum of money is divided between A and B in the ratio of 5/4 : 5/3 and A got Rs. 360/-. Find the total sum of money and B’s share? A) 480 B) 120 C) 240 D) 540 Correct Answer : 480 Explanation :Let the share of B be X Given ratios are A : B = 5/4 : 5/3 = 15/20 = 3/4 Now 360/X = 3/4 So B's share, X=480 total sum of money = 360+480 = 840 In an office, the ratio of the salaries of an officer and a clerk is 15:7. If the salary of a clerk is Rs. 720/- less than the salary of the officer, find the salary of each? A) 1000 ,600 B) 1050 ,630 C) 1250 ,60 D) 1350 ,630 Correct Answer : 1350 ,630 Explanation :Let the salary of officer is X and clerk is Y as is given X/Y = 15/7 ---eq 1 X-Y = 720 ----eq 2 from eq1 X=15Y/7 and substituting it in eq2 15Y/7 - Y =720 8Y= 720*7 Hence salary of clerk is, Y = 630 and salary of officer is, X = 15Y/7 = 15*630/7 = 1350 In an election to a municipal council, the votes secured by two candidates are in the ratio 13:19. The elected candidates gets 312 votes more than the second candidate. How many votes are secured by the second candidate? A) 500 B) 620 C) 676 D) 700 Correct Answer : 676 Explanation :Let the two candidates are A and B the ratio is 13:19 So, A's votes = 13x B's votes = 19x As is given 19X - 13X = 312 6X = 312 X = 52 Hence A's votes= 13X = 13*52 =676 and B's votes= 19X = 19*52 = 988 the second candidate is secured 676 votes A certain sum of money is divided between Murthy and Prasad in the ratio 22/7 : 8/3. If Murthy gets Rs. 120/- more than Prasad, find the share of each? A) 700,600 B) 792,672 C) 892,770 D) 998,772 Correct Answer : 792,672 Explanation :The ratio is 22/7 : 8/3 = 22*3/7*8 = 33/28 So, Murthy's share = 33X Prasad's share = 28X As is given 33X - 28X = 120 5X = 120 X = 24 Hence Murthy's share = 33X = 33*24 = 792 and Prasad's share= 28X = 28*24 = 672 In a cricket test series, the runs made by Raju and Tendulkar are in the ratio 5:9 and Tendulkar and Azar are in the ratio 6:7. What are the runs made by them if Azar makes 187 runs more than Raju? A) 110,126,250 B) 120,216,307 C) 170,306,357 D) 168,206,352 Correct Answer : 170,306,357 Explanation :The ratio is R/T = 5/9 = 5*6/9*6 T/A = 6/7 = 6*9/7*9 So, rotio of their runs R:T:A = 5*6:9*6:7*9 = 5*2:9*2:7*3 = 10:18:21 As is given 21X - 10X = 187 11X = 187 X = 17 Therefore Raju's runs= 10X = 10*17 = 170 Tendulkar's runs= 18X = 18*17 = 306 Azar's runs= 21X = 21*17 = 357 Annual incomes of the families of Sita and Latha are in the ratio 4:3 and their annual expenditure are in the ratio 3:2. What is their annual income if they save Rs 3000/- in a year? A) 10000,7000 B) 11000,8000 C) 12000,9000 D) 13000,10000 Correct Answer : 12000,9000 Explanation :Let annual income of the families of Sita and Latha be 4x and 3x, and expenditure be 3y and 2y respectively As is given Saving of families of Sita 4x−3y=3000 ---(1) Saving of families of Latha 3x−2y=3000 ---(2) After resolving eq 1 and 2 8x−6y=6000 9x−6y=9000 x=3000 Hence, Annual income of the families of Sita=4x=12000 Annual income of the families of Latha=3x=9000 The cost of 10 books is Rs. 80/-. Find the value of 15 books? A) 90 B) 100 C) 110 D) 120 Correct Answer : 120 Explanation :Let the cost of a book is X As is given 10X = 80 rs X=80/10 X=8 Hence, value of 15 books= 15*X =15*8 =120 Rs The cost of 48 bags of paddy is Rs. 16,800/-. What is the cost of 36 bags of paddy? A) 12400 B) 12600 C) 12800 D) 13000 Correct Answer : 120 Explanation :Let the cost of 36 bags is X, Then 48 bags of paddy : 36 bags of paddy = Rs 16800 : X X = 16800*36 / 48 Hence, the cost of 36 bags is X =12600 Monthly expenditure of a family of 4 members is Rs 2800/-. What is the expenditure if there are 3 members in the family? A) 1900 B) 2000 C) 2100 D) 2200 Correct Answer : 2100 Explanation :Let the expenditure of 3 members in the family is X Then expenditure of 4 members : expenditure of 3 members = Rs 2800 : X X = 2800*3 / 4 X = 2100 Hence, expenditure of 3 members is, X = 2100 Find the mean proportional between 8 and 32 ? A) 12 B) 13 C) 14 D) 16 Correct Answer : 16 Explanation :Mean proportional between a and b is square root of ab. Mean Proportional= √(8*32) =16 The mess charge for 35 students for 24 days is Rs. 6300/-. In how many days will the mess charges be Rs. 3375/- for 25 students? A) 12 B) 14 C) 18 D) 22 Correct Answer : 18 Explanation :The rate for one student per day is the same, so 35 students*24 days / 25 students* X days = 6300 Rs/3375 Rs 35*24*3375 = 6300*25*X X = 35*24*3375 / 6300*25 X = 18 Rice costing Rs. 480/- is needed for 8 members for 20 days. What is the cost of rice required for 12 members for 15 days? A) 540 B) 320 C) 450 D) 560 Correct Answer : 540 Explanation :cost of rice for 8 members in a family for 20 days = 480 Rs cost of rice for 1 members for 1 day= 480/ 8*20 = 24 Rs Now cost of rice for 12 members for 15 days= 480*12*15 / 8*20 = 540 Rs 10 men can lay a road of 75 Km long in 5 days. In how many days can 15 men lay a road of 45 Km long? A) 4 B) 3 C) 2 D) 1 Correct Answer : 2 Explanation :10 men*5 days / 15 men*X days = 75 Km/45 Km 10*5*45 = 75*15*X X = 10*5*45 / 75*15 X = 2 Therefore, 15 men can lay a road of 45 Km long in 2 days 24 men working at 8 hours a day can do a piece of work in 15 days. In how many days can 20 men working at 9 hours a day do the same work? A) 12 B) 14 C) 16 D) 18 Correct Answer : 16 Explanation :People* hours* days is always constant. So let the required day be X. 24 * 8 * 15 = 20 * 9 * X X = 24 * 8 * 15 / 20 * 9 X = 16 On solving it, 20 men working at 9 hours a day required 1616 days to complete the same work