Average- Aptitude Questions and Answers - in Hindi

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Among five people with monthly income of Rs. 14000, Rs. 25000, Rs. 15000, Rs. 18000 and Rs.49000, how many will have income less than the mean income of the five people?


14000 रुपये 25000 रुपये 15000 रुपये 18000 रुपये और 49000 रुपये की मासिक आय वाले पांच लोगों में से कितने लोगों की आय, पाँचो की औसत आय से कम होगी?

A)

1


B)

2


C)

3


D)

4



Correct Answer :

3


Explanation :

Avrage value = (14000+25000+15000+18000+49000) / 5 = 24200

3 person has less income than mean income

The average of the marks obtained by three girls in a test was twice the average of the marks obtained by eight boys in that test. If the total marks obtained by all these examinees was 168, find the average marks each of the girls obtained ?


एक परीक्षा में तीन लड़कियों द्वारा प्राप्त अंकों का औसत उस परीक्षा में आठ लड़कों द्वारा प्राप्त अंकों के औसत से दोगुना था। यदि इन सभी परीक्षार्थियों द्वारा प्राप्त किए गए कुल अंक 168 थे, तो प्रत्येक लड़कियों का औसत प्राप्त अंक ज्ञात कीजिए?

A)
25

B)
12

C)
24

D)
14


Correct Answer :

24


Explanation :

let avg marks of boys= X
number of boys = 8
sum of marks of boys =8X

as is given, avg marks of girls = 2X
number of girls =3
sum of marks of girls= 6X

Now, total sum of marks obtained = 168 = 8X+6X
X = 168/14 = 12

avg marks of girls = 2X =2*12 =24

The mean of 100 students marks was found to be 40. it was found later that a mark 53 was read as 83. the correct mean is?


100 छात्रों के अंकों का माध्य 40 पाया गया। बाद में पता चला कि एक अंक 53 को गलती से 83 के रूप में पढ़ा गया था। तो सही माध्य होगा?

A)
40.30

B)
40.70

C)
39.40

D)
39.70


Correct Answer :

39.70


Explanation :

As given, mean marks of 100 students = 40
mean = sum of observation / no of observations
Sum of marks = 100 * 40 = 4000
Given that one observation is misread as 53 instead of 83
Hence after replacement, correct sum of observations = 4000 - 83 + 53 = 3970
Correct mean =sum of new observation / no of observations = 3970/100 = 39.7

Find the average. 62, 54, 44, 36, 28 & 22


औसत ज्ञात कीजिए. 62, 54, 44, 36, 28 & 22

A)

39


B)

40


C)

41


D)

42



Correct Answer :

41


Explanation :

Average = Sum of all the observations / Number of observation
Average = (62 + 54 + 44 + 36 + 28 + 22) / 6 = 41

So the average of the given numbers is 41.

In the world cup, Yuvraj has a batting average of 65 in 7 matches till semi-final. How much should Yuvraj score in the 8th match ie the final match to get a batting average of 85?


विश्व कप में, सेमीफाइनल तक 7 मैचों में युवराज का बल्लेबाजी औसत 65 था। युवराज को 8वें मैच में कितना स्कोर करना चाहिए कि फाइनल मैच में बल्लेबाजी औसत 85 का हो जाये ?

A)
230

B)
215

C)
220

D)
225


Correct Answer :

225


Explanation :

Sum of values = Average of values * Number of values
So,
Total score of Yuvraj in 7 matches = 65 * 7 = 455
Total score of Yuvraj after 8th match (final) = 85 * 8 = 680

Score in the 8th match = Total score after 8th match - Total score in 7 matches
=680 – 455
=225

Therefore Yuvraj should score 225 in the 8th match to get a batting average of 85.

The average mark of 50 students is 75. If the marks obtained by one of the student had been written as 36 instead of 86, then the corrected average of marks is:


50 छात्रों के अंको का औसत 75 है। यदि किसी एक छात्र द्वारा प्राप्त 86 अंको को 36 लिख दिया जाये, तो अंकों का सही औसत है:

A)

51


B)

76


C)

36


D)

61



Correct Answer :

76


Explanation :

Sum of values = Average of values × Number of values
The total marks obtained by 50 students = 75 * 50 = 3750

Marks of one student is written as 36 instead of 86.
Actual marks = 3750 + (86 – 36)
=3750 + 50
=3800

Hence correct average = Actual marks/total number of students
=3800/50
=76

The sum of two numbers is 15 and their geometric mean is 20% lower than their arithmetic mean. Find the numbers?


दो संख्याओं का योग 15 है और उनका गुणोत्तर माध्य उनके समांतर माध्य से 20% कम है। संख्याएँ ज्ञात कीजिए?

A)

11,4


B)
12,3

C)
13,2

D)
10,5


Correct Answer :

12,3


Explanation :

Let the numbers be x and y.
x+y = 15, or
y = 15 - x ...…(1)
GM= (xy)^1/2
AM = (x+y)/2 = 15/2

As given,
GM = AM - 20% of AM
GM = AM( 1 - 20/100)
(xy)^1/2 = [(x+y)/2]*80/100
(xy)^1/2 = 15/2 * 80/100 = 6
Square both sides

xy =6^2 = 36
y = 36/x ...…(2)

Equate (1) and (2)
15-x = 36/x, or
x^2–15x+36=0
(x-12)(x-3) = 0
So x = 12 or 3 and y = 3 or 12.

So the two numbers are 3 and 12.

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