# Races And Games- Aptitude Questions and Answers

 In a 100m race,A covers the distance in 36 sec and B in 45 sec.In this race A beats B by? A) 20 m B) 22 m C) 25 m D) 30 m Correct Answer : 20 m Explanation :Distance covered by B in 9secs =100*9/45 =20 m So, A beats B by 20m Post/View Answer Post comment Cancel Thanks for your comment.! Write a comment(Click here) ...
 In a kilometer race, A can beat B by 100 m and B can beat C by 80 m. If A and C run in the same race, by how many meters will A win? A) 172 m B) 178 m C) 220 m D) 200 m Correct Answer : 172 m Explanation :In a km race A can beat B by 100 m ie A run 1000 m, B run (1000-100)=900 m In a km race B can beat C by 80 m ie B runs 1000 m, C runs (1000-80)=920 m so B run 1 m, C run 920/1000 m ie B runs 900 m, C runs (920/1000)×900=92×9=828 m ie A run 1000 m,B runs 900 m and C run 828 m Hence, A can beat C by (1000-828)=172 m Raman covers 1 km in 8 min while suman covers the same distance in 10 min. By what distance does Raman beat Suman ? A) 150 m B) 65 m C) 190 m D) 200 m Correct Answer : 200 m Explanation :Raman covers 1 km in 8 min and suman cover 1 km in 10 min. If they starts together, then distance covered by suman in 8 min = (1000/10) x 8 = 800 m Thus, Raman will beat suman by (1000 - 800 ) m = 200 m In 1 km race, A beats B by 18 m or 9 s. Find the A' s time over the course? A) 391 s B) 591 s C) 491 s D) 500 s Correct Answer : 491 s Explanation :Clearly, B covers 18 m in 9 s. B's time over the course = 9/18 x 1000 = 500 s A' s time over the course = (500 - 9) = 491 s In a 100 m race A runs at a speed of 5/3 m/s. If A give a start of 4 m to B and still beats him by 12 seconds, what is speed of B? A) 5/4 m/s B) 7/5 m/s C) 4/3 m/s D) 6/5 m/s Correct Answer : 4/3 m/s Explanation :Let the distance is 100 m and speed of B be x m/s. Then, according to the question 96/x - 100/(5/3) = 12 96/x - 60 = 12 96/x = 72 x = 96/72 x = 4/3 Speed of B is 4/3 m/s. In a 1 km race,A beats B by 28 m or 7 sec.Find A's time over the course? A) 2 min ,2 sec B) 3 min ,3 sec C) 4 min ,3 sec D) 5 min ,4 sec Correct Answer : 4 min ,3 sec Explanation :B covers 28 m in 7 sec so,B's time over the course = 7/28 *1000 =250 sec A's time over the course =250-7 =243 sec = 4 min ,3 sec. A runs 7/4 times as fast as B.If A gives B a start of 84 m,how far must be winning post be so that A and B might reach it at the same time ? A) 84 m B) 121 m C) 154 m D) 196 m Correct Answer : 196 m Explanation :If A runs 7/4 times as fast as B ⇒ A : B =7/4 :1 = 7 : 4 Define x: Let x be the constant ratio A : B = 7x : 4x Solve x: The difference is 84m 7x - 4x = 84 3x = 84 x = 28m Find the distance of the winning post: The winning post is the distance A has to run A = 7x = 7*28m = 196 m Winning post must be 196 m away from the starting point A can run 1 km in 3 min ,10 sec and B can cover same distance in 3 min 20 sec. By what distance A beat B? A) 50 m B) 40 m C) 60 m D) 80 m Correct Answer : 50 m Explanation :A can run 1 km in 3 min 10 sec and B can cover same distance in 3 min 20 sec. Clearly A beats B by 10 sec. Distance covered by B in 3 min 20 sec ie 1000m in 2000sec Distance covered by B in 10 sec =1000/200 *10 =50 m A beats B by 50 meter. In a 100 m race,A runs at 8 km per hour.If A gives B a start of 4 m and still beats him by 15 sec,what is the speed of B? A) 3.7 km/hr B) 4.16 km/hr C) 5.76 km/hr D) 7.71 km/hr Correct Answer : 5.76 km/hr Explanation :A's speed 8 km per hr ie 8000 m -------60*60 sec 100 m ------- 60*60*1000/8000 =45 sec Time taken by A to cover 100 m =45 sec B covers 100-4 m =96 m Time taken by B to cover 100m=Time taken by A + 15 Sec =45 sec + 15 Sec = 60 Sec B's speed =96 m/60 sec = 96*60*60 km/60*1000 hr =5.76 km/hr A and B take part in 100 m race .A runs at 5 km per hour. A gives B a start of 8 m and still beats him by 8 sec. What is the speed of B? A) 6.14 km/hr B) 2.16 km/hr C) 5.14 km/hr D) 4.14 km/hr Correct Answer : 4.14 km/hr Explanation : 1 km/hr = 1000/60*60 =5/18 m/sec A'speed = 5 km/hr =5*5/18 =25/18 m/s Time taken by A to cover 100 m =100*18/25 =72 sec B covers 100-8 m =92 m Time taken by B to cover 92 m = Time taken by A + 8 Sec =72 sec + 8 Sec = 80 sec B's speed =92/80 m/s = 92*18/80*5 km/hr = 4.14 km/hr A runs 5/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach at the same time? A) 200 m B) 300 m C) 240 m D) 340 m Correct Answer : 200 m Explanation :Ratio of the speed of A and B = 5/3 :1 ⇒ A : B = 5 : 3 Let x be the constant ratio A : B = 5x : 3x The difference is 80 m 5x - 3x = 80 x = 40 m The winning post is the distance A has to run A = 5x = 5*80m = 200 m Winning post must be 200 m away from the starting point A, B and C are the three contestants in one km race. If A can give B a start of 40 metres and A can give C a start of 64 metres, how many metres start can B give C? A) 20 m B) 21 m C) 25 m D) 34 m Correct Answer : 25 m Explanation :Ratio of the speed of A and B = A : B = 1000:960 Ratio of the speed of A and C = A : C = 1000:936 So ratio of the speed of B and C => B : C = 960:936 = (960+40):(936+40) = 1000:975 That is, B can give C a start of 25 metres. In a 200 m race A beats B by 35 m or 7 sec.What is the A's time over the course? A) 12 sec B) 19 sec C) 33 sec D) 45 sec Correct Answer : 33 sec Explanation :B runs 35 m in 7 sec B covers 200 m in (7/35*200) = 40 sec B's time over the course = 40 sec A's time over the course (40 - 7) sec = 33 sec In a 300 m race A beats B by 22.5 m or 6 sec.What is the B's time over the course? A) 92 sec B) 80 sec C) 73.5 sec D) 65 sec Correct Answer : 80 sec Explanation : B runs 22.5 m in 6 sec B runs 300m in =6*300/22.5 =80 sec B's time over the course =80 sec A can run 22.5 m while B runs 25 m.In a kilometre race B beats A by? A) 100 m B) 140 m C) 180 m D) 200 m Correct Answer : 100 m Explanation :B runs 25 m ,A runs 22.5 m B runs 1000, A runs = 1000*25/22.5 =900 m B beats A by (1000-900)m = 100 m In a 500 m race, the ratio of the speeds of two contestants A and B is 3:4. A has a start of 140 m.Then ,A win by B? A) 10 m B) 14 m C) 18 m D) 20 m Correct Answer : 20 m Explanation :A covers 500-140 = 360 m Ratio of speeds of A:B = 3:4 Let us consider A covers 3m/sec & B covers 4m/sec Time taken by A to cover 360m=(360/3)=120 sec So,Distance covered by B in 120s =120*4=480m Therefore,A wins by (500-480)= 20 metres In a 100m race,A can beat B by 25 m and B can beat C by 4m.In the same race A can beat by C? A) 14 m B) 28 m C) 42 m D) 56 m Correct Answer : 28 m Explanation :Ratio of speeds of A:B =100 :75 Ratio of speeds of B :C=100 :96 then Ratio of speeds of A :C =A/B*B/C =100/75* 100/96 = 100/72 So, A beats C by 100 - 72 m=28 m