Except U, the remaining letters represents the square number positions in English alphabet.
Position number of letters in English alphabets-
A =1=1^{2}
D=4=2^{2}
Y=25=5^{2}
U=21

A clock buzzes 1 time at 1 O’clock, 2 times at 2 O’clock, 3 times at 3 O’clock and so on. What will be the total number of buzzes by the clock in a day?

A)

150

B)

156

C)

100

D)

None of these

Your Answer : (Not Answered) Correct Answer :

156

Explanation :

The 24 hours in a day therefore the total number of buzzes = (1+2+3+4+5+6+7+8+9+10+11+12)+(1+2+3+4+5+6+7+8+9+10+11+12)

as (1 + 2 + 3 +…. + n) =n(n+1)/2
So total number of buzzes = (12*(1+12)/2) + (12*(1+12)/2) = 78+78 =156

In the given series one number is missing. Understand the pattern of the series and insert the number.
4, 7, 9, 12, 14, 17, ?, 22

A)

21

B)

19

C)

18

D)

20

Your Answer : (Not Answered) Correct Answer :

19

Explanation :

the pattern of the series is
4,(4+3)=7 ,(7+2)=9 ,(9+3)=12 ,(12+2)=14 ,(14+3)=17 ,(17+2)=19 ,(19+3)=22
and according to pattern the missing number is 19

In a certain code ‘come back soon’ is written as ‘9 4 3’, ‘soon hear all’ is written as ’4 1 2’, and ‘come all’ is written as ‘2 9’, What is the code for ‘hear’?

A)

1

B)

3

C)

2

D)

4

Your Answer : (Not Answered) Correct Answer :

1

Explanation :

‘come back soon’ = ‘9 4 3’ ------eq(i)
‘soon hear all’ = ’4 1 2’ ------eq(ii)
‘come all’ = ‘2 9’ ------eq(iii)
from eq(i) and (ii), soon=4
from eq(ii) and (iii), all=2
Therefore, eq(ii) hear=1

A cube of side 12 cm is painted red on all faces and cut into smaller cubes each of 3 cm each. What is the total number of smaller cubes having none of their faces painted?

A)

8

B)

12

C)

16

D)

24

Your Answer : (Not Answered) Correct Answer :

8

Explanation :

A cube of side 12 cm is cut into smaller cube of side 3 cm. So, one side of big cube equals 4 sides of smaller cube.
The big cube divided into 4 x 4 x 4 = 64 smaller cubes.
There are 8 original corners on the original cube having 3 painted sides = 8 cubes
There are 12 edges on the original cube, each edge has 2 cubes with 2 painted sides,12 edges *2 cubes =24 cubes
There were 6 faces, each with 4 cubes with one painted side, 6 faces *4 cubes = 24 cubes Therefore, cubes which don't have any coloured side= 64 - 8 - 24 - 24 = 8 cubes