A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days. B alone can do the entire work in?

A)

60 days

B)

54 days

C)

50 days

D)

48 days

Your Answer : (Not Answered) Correct Answer :

60 days

Explanation :

Amount of work done by A and B in 1 day = 1/30
Amount of work done by both in 20 days = 20 * (1/30) = 2/3
Remaining work = 1 - 2/3 = 1/3
Given, A completes 1/3 work in 20 days.
Therefore, A can finish the whole work in (20 x 3) = 60 days.

Work done by A and B in 1 day, A+B = 1/30
A = 1/60 then Work done by B = 1/30 - 1/60 = 1/60
So B alone can finish the work in 60 days.

One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram?

A)

12.56 cm^{2}

B)

14.56 cm^{2}

C)

16.76 cm^{2}

D)

22.56 cm^{2}

Your Answer : (Not Answered) Correct Answer :

16.76 cm^{2}

Explanation :

Area of parallelogram = base x height
= 8.06 x 2.08 = 16.76 cm^{2}

My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when i was born. If my sister was 4 years of age when my brother was born,then what was the age my father and mother respectively when my brother was born?

A)

32 years, 23 years

B)

32 years, 29 years

C)

35 years, 29 years

D)

35 years, 33 years

Your Answer : (Not Answered) Correct Answer :

32 years, 23 years

Explanation :

Father was 28 years of age when my sister was born.
My brother was born 4 years after my sister was born.
Then Father's age when brother was born = 28+4 = 32 years.

Mother was 26 years of age when I was born.
My brother was born 3 years before I was born,
Then Mother's age when brother was born = 26-3 = 23 years.

A tank is filled by 3 pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The 2nd pipe fills the tank 5 hours faster than first pipe and 4 hours slower than third pipe. The time required by first pipe is?

A)

6 hours

B)

10 hours

C)

15 hours

D)

30 hours

Your Answer : (Not Answered) Correct Answer :

15 hours

Explanation :

Suppose, first pipe take x hours to fill the tank then
B & C will take (x-5) and (x-9) hours respectively.
Therefore, 1/x +1/(x-5) =1/(x-9)
On solving, x=15
Hence, time required by first pipe is 15 hours.

Sachin is younger than Ajay by 7 years. If the ratio of their ages is 7:9, find the age of Sachin ?

A)

24

B)

23.5

C)

25

D)

24.5

Your Answer : (Not Answered) Correct Answer :

24.5

Explanation :

Let Ajay age is x, then Sachin age is x-7,
So, Sachin’s Age / Ajay ’s Age => (x-7)/x = 7/9
9(x – 7) = 7x
9x-63 = 7x
9x – 7x = 63
2x = 63
x = 31.5
So Sachin age is, x-7 => 31.5 - 7 = 24.5

In an election to a municipal council, the votes secured by two candidates are in the ratio 13:19. The elected candidates gets 312 votes more than the second candidate. How many votes are secured by the second candidate?

A)

500

B)

620

C)

676

D)

700

Your Answer : (Not Answered) Correct Answer :

676

Explanation :

Let the two candidates are A and B
the ratio is 13:19
So,
A's votes = 13x
B's votes = 19x

As is given
19X - 13X = 312
6X = 312
X = 52
Hence A's votes= 13X = 13*52 =676
and B's votes= 19X = 19*52 = 988

Two pipes A and B can fill a tank in 36 min and 45 min respectively. A water pipe C can empty the tank in 30 min. First A and B are opened. after 7 min, C is also opened. In how much time, the tank is full?

A)

36 min

B)

38 min

C)

42 min

D)

46 min

Your Answer : (Not Answered) Correct Answer :

46 min

Explanation :

Part filled n 7 min = 7*(1/36+1/45)=7/20
Remaining part= 1-7/20=13/20
Net part filled in 1 min when A,B and C are opened=1/36 +1/45- 1/30=1/60
Now, 1/60 part is filled in 1 min.
13/20 part is filled n (60*13/20)=39 min
Total time taken to fill the tank=39+7=46 min